elanna89 asked:


The normal boiling point of liquid ethanol is 351 K. Assuming that its molar heat of vaporization is constant at 37.5 kJ/mol, the boiling point of C2H5OH when the external pressure is 1.33 atm is _____K.

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1 Comment so far

1. SciMann September 16, 2009 2:40 am

   _____The Clausius-Clapeyron equation to estimate the vapor pressure at another temperature, if the vapor pressure is known at some temperature, …

   ln(P2/P1) = – (dHvap /R) * (1/T2- 1/T1)

   ln(1.33atm/1atm) = -(37500J/mole / 8.314J/moleK) * (1/T(K) – 1/351K)

   SOLVE for T(K)

   Basic mathematics is a prerequisite to chemistry – I just try to help you with the methodology of solving the problem.

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